Metamath Proof Explorer


Theorem animorrl

Description: Conjunction implies disjunction with one common formula (4/4). (Contributed by BJ, 4-Oct-2019)

Ref Expression
Assertion animorrl ⊢ φ ∧ ψ → ψ ∨ χ

Proof

Step Hyp Ref Expression
1 simpr ⊢ φ ∧ ψ → ψ
2 1 orcd ⊢ φ ∧ ψ → ψ ∨ χ