Metamath Proof Explorer


Theorem ax8v1

Description: First of two weakened versions of ax8v , with an extra disjoint variable condition on x , z , see comments there. (Contributed by BJ, 7-Dec-2020)

Ref Expression
Assertion ax8v1 ⊢ x = y → x ∈ z → y ∈ z

Proof

Step Hyp Ref Expression
1 ax8v ⊢ x = y → x ∈ z → y ∈ z