Metamath Proof Explorer


Theorem axaci

Description: Apply a choice equivalent. (Contributed by Mario Carneiro, 17-May-2015)

Ref Expression
Hypothesis axaci.1 ⊢ CHOICE ↔ ∀ x φ
Assertion axaci ⊢ φ

Proof

Step Hyp Ref Expression
1 axaci.1 ⊢ CHOICE ↔ ∀ x φ
2 axac3 ⊢ CHOICE
3 2 1 mpbi ⊢ ∀ x φ
4 3 spi ⊢ φ