Metamath Proof Explorer


Theorem bj-abf

Description: Shorter proof of abf (which should be kept as abfALT). (Contributed by BJ, 24-Jul-2019) (Proof modification is discouraged.)

Ref Expression
Hypothesis bj-abf.1 ¬φ
Assertion bj-abf x|φ=

Proof

Step Hyp Ref Expression
1 bj-abf.1 ¬φ
2 bj-ab0 x¬φx|φ=
3 2 1 mpg x|φ=