Metamath Proof Explorer


Theorem bj-abf

Description: Shorter proof of abf (which should be kept as abfALT). (Contributed by BJ, 24-Jul-2019) (Proof modification is discouraged.)

Ref Expression
Hypothesis bj-abf.1 ⊢ ¬ φ
Assertion bj-abf ⊢ x | φ = ∅

Proof

Step Hyp Ref Expression
1 bj-abf.1 ⊢ ¬ φ
2 bj-ab0 ⊢ ∀ x ¬ φ → x | φ = ∅
3 2 1 mpg ⊢ x | φ = ∅