Metamath Proof Explorer


Theorem chndun

Description: Chains in either of two alphabets are chains in their union. (Contributed by Ender Ting, 24-Jul-2026)

Ref Expression
Assertion chndun ⊢ A ∈ Chain B R ∨ A ∈ Chain C R → A ∈ Chain B ∪ C R

Proof

Step Hyp Ref Expression
1 ssun1 ⊢ B ⊆ B ∪ C
2 chndss ⊢ B ⊆ B ∪ C → Chain B R ⊆ Chain B ∪ C R
3 1 2 ax-mp ⊢ Chain B R ⊆ Chain B ∪ C R
4 3 sseli ⊢ A ∈ Chain B R → A ∈ Chain B ∪ C R
5 ssun2 ⊢ C ⊆ B ∪ C
6 chndss ⊢ C ⊆ B ∪ C → Chain C R ⊆ Chain B ∪ C R
7 5 6 ax-mp ⊢ Chain C R ⊆ Chain B ∪ C R
8 7 sseli ⊢ A ∈ Chain C R → A ∈ Chain B ∪ C R
9 4 8 jaoi ⊢ A ∈ Chain B R ∨ A ∈ Chain C R → A ∈ Chain B ∪ C R