Metamath Proof Explorer


Theorem dfsb7OLD

Description: Obsolete version of dfsb7 as of 3-Sep-2023. (Contributed by NM, 28-Jan-2004) Revise df-sb . (Revised by BJ, 25-Dec-2020) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion dfsb7OLD t x φ y y = t x x = y φ

Proof

Step Hyp Ref Expression
1 df-sb t x φ y y = t x x = y φ
2 sb56 y y = t x x = y φ y y = t x x = y φ
3 sb56 x x = y φ x x = y φ
4 3 bicomi x x = y φ x x = y φ
5 4 anbi2i y = t x x = y φ y = t x x = y φ
6 5 exbii y y = t x x = y φ y y = t x x = y φ
7 1 2 6 3bitr2i t x φ y y = t x x = y φ