Metamath Proof Explorer


Theorem dihordlem6

Description: Part of proof of Lemma N of Crawley p. 122 line 35. (Contributed by NM, 3-Mar-2014)

Ref Expression
Hypotheses dihordlem8.b ⊢ B = Base K
dihordlem8.l ⊢ ≤ ˙ = ≤ K
dihordlem8.a ⊢ A = Atoms ⁡ K
dihordlem8.h ⊢ H = LHyp ⁡ K
dihordlem8.p ⊢ P = oc ⁡ K ⁡ W
dihordlem8.o ⊢ O = h ∈ T ⟼ I ↾ B
dihordlem8.t ⊢ T = LTrn ⁡ K ⁡ W
dihordlem8.e ⊢ E = TEndo ⁡ K ⁡ W
dihordlem8.u ⊢ U = DVecH ⁡ K ⁡ W
dihordlem8.s ⊢ + ˙ = + U
dihordlem8.g ⊢ G = ι h ∈ T | h ⁡ P = R
Assertion dihordlem6 ⊢ K ∈ HL ∧ W ∈ H ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ R ∈ A ∧ ¬ R ≤ ˙ W ∧ s ∈ E ∧ g ∈ T → s ⁡ G s + ˙ g O = s ⁡ G ∘ g s

Proof

Step Hyp Ref Expression
1 dihordlem8.b ⊢ B = Base K
2 dihordlem8.l ⊢ ≤ ˙ = ≤ K
3 dihordlem8.a ⊢ A = Atoms ⁡ K
4 dihordlem8.h ⊢ H = LHyp ⁡ K
5 dihordlem8.p ⊢ P = oc ⁡ K ⁡ W
6 dihordlem8.o ⊢ O = h ∈ T ⟼ I ↾ B
7 dihordlem8.t ⊢ T = LTrn ⁡ K ⁡ W
8 dihordlem8.e ⊢ E = TEndo ⁡ K ⁡ W
9 dihordlem8.u ⊢ U = DVecH ⁡ K ⁡ W
10 dihordlem8.s ⊢ + ˙ = + U
11 dihordlem8.g ⊢ G = ι h ∈ T | h ⁡ P = R
12 simp1 ⊢ K ∈ HL ∧ W ∈ H ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ R ∈ A ∧ ¬ R ≤ ˙ W ∧ s ∈ E ∧ g ∈ T → K ∈ HL ∧ W ∈ H
13 simp2r ⊢ K ∈ HL ∧ W ∈ H ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ R ∈ A ∧ ¬ R ≤ ˙ W ∧ s ∈ E ∧ g ∈ T → R ∈ A ∧ ¬ R ≤ ˙ W
14 simp2l ⊢ K ∈ HL ∧ W ∈ H ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ R ∈ A ∧ ¬ R ≤ ˙ W ∧ s ∈ E ∧ g ∈ T → Q ∈ A ∧ ¬ Q ≤ ˙ W
15 simp3 ⊢ K ∈ HL ∧ W ∈ H ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ R ∈ A ∧ ¬ R ≤ ˙ W ∧ s ∈ E ∧ g ∈ T → s ∈ E ∧ g ∈ T
16 1 2 3 4 5 6 7 8 9 10 11 cdlemn6 ⊢ K ∈ HL ∧ W ∈ H ∧ R ∈ A ∧ ¬ R ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ s ∈ E ∧ g ∈ T → s ⁡ G s + ˙ g O = s ⁡ G ∘ g s
17 12 13 14 15 16 syl121anc ⊢ K ∈ HL ∧ W ∈ H ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ R ∈ A ∧ ¬ R ≤ ˙ W ∧ s ∈ E ∧ g ∈ T → s ⁡ G s + ˙ g O = s ⁡ G ∘ g s