Metamath Proof Explorer


Theorem disjdifg

Description: A class does not intersect a relative complement of a superclass. (Contributed by NM, 24-Mar-1998) Generalize from disjdif . (Revised by BJ, 19-Jul-2026)

Ref Expression
Assertion disjdifg ⊢ A ⊆ B → A ∩ C ∖ B = ∅

Proof

Step Hyp Ref Expression
1 ssinss1 ⊢ A ⊆ B → A ∩ C ⊆ B
2 inssdif0 ⊢ A ∩ C ⊆ B ↔ A ∩ C ∖ B = ∅
3 1 2 sylib ⊢ A ⊆ B → A ∩ C ∖ B = ∅