Metamath Proof Explorer


Theorem disjimin

Description: Disjointness condition for intersection. (Contributed by Peter Mazsa, 11-Jun-2021) (Revised by Peter Mazsa, 28-Sep-2021)

Ref Expression
Assertion disjimin ⊢ Disj S → Disj R ∩ S

Proof

Step Hyp Ref Expression
1 inss2 ⊢ R ∩ S ⊆ S
2 1 disjssi ⊢ Disj S → Disj R ∩ S