Metamath Proof Explorer


Theorem div11d

Description: One-to-one relationship for division. (Contributed by Mario Carneiro, 27-May-2016)

Ref Expression
Hypotheses div1d.1 ⊢ φ → A ∈ ℂ
divcld.2 ⊢ φ → B ∈ ℂ
divmuld.3 ⊢ φ → C ∈ ℂ
divassd.4 ⊢ φ → C ≠ 0
div11d.5 ⊢ φ → A C = B C
Assertion div11d ⊢ φ → A = B

Proof

Step Hyp Ref Expression
1 div1d.1 ⊢ φ → A ∈ ℂ
2 divcld.2 ⊢ φ → B ∈ ℂ
3 divmuld.3 ⊢ φ → C ∈ ℂ
4 divassd.4 ⊢ φ → C ≠ 0
5 div11d.5 ⊢ φ → A C = B C
6 div11 ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ C ≠ 0 → A C = B C ↔ A = B
7 1 2 3 4 6 syl112anc ⊢ φ → A C = B C ↔ A = B
8 5 7 mpbid ⊢ φ → A = B