Metamath Proof Explorer


Theorem divrecd

Description: Relationship between division and reciprocal. Theorem I.9 of Apostol p. 18. (Contributed by Mario Carneiro, 27-May-2016)

Ref Expression
Hypotheses div1d.1 ⊢ φ → A ∈ ℂ
divcld.2 ⊢ φ → B ∈ ℂ
divcld.3 ⊢ φ → B ≠ 0
Assertion divrecd ⊢ φ → A B = A ⁢ 1 B

Proof

Step Hyp Ref Expression
1 div1d.1 ⊢ φ → A ∈ ℂ
2 divcld.2 ⊢ φ → B ∈ ℂ
3 divcld.3 ⊢ φ → B ≠ 0
4 divrec ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ B ≠ 0 → A B = A ⁢ 1 B
5 1 2 3 4 syl3anc ⊢ φ → A B = A ⁢ 1 B