Metamath Proof Explorer


Theorem divreczi

Description: Relationship between division and reciprocal. Theorem I.9 of Apostol p. 18. (Contributed by NM, 11-Oct-1999)

Ref Expression
Hypotheses divclz.1 A
divclz.2 B
Assertion divreczi B0AB=A1B

Proof

Step Hyp Ref Expression
1 divclz.1 A
2 divclz.2 B
3 divrec ABB0AB=A1B
4 1 2 3 mp3an12 B0AB=A1B