Metamath Proof Explorer


Theorem dmqseqd

Description: Equality theorem for domain quotient set, deduction version. (Contributed by Peter Mazsa, 23-Apr-2021)

Ref Expression
Hypothesis dmqseqd.1 ⊢ φ → R = S
Assertion dmqseqd ⊢ φ → dom ⁡ R / R = dom ⁡ S / S

Proof

Step Hyp Ref Expression
1 dmqseqd.1 ⊢ φ → R = S
2 dmqseq ⊢ R = S → dom ⁡ R / R = dom ⁡ S / S
3 1 2 syl ⊢ φ → dom ⁡ R / R = dom ⁡ S / S