Metamath Proof Explorer


Theorem dsid

Description: Utility theorem: index-independent form of df-ds . (Contributed by Mario Carneiro, 23-Dec-2013)

Ref Expression
Assertion dsid ⊢ dist = Slot dist ⁡ ndx

Proof

Step Hyp Ref Expression
1 df-ds ⊢ dist = Slot 12
2 1nn0 ⊢ 1 ∈ ℕ 0
3 2nn ⊢ 2 ∈ ℕ
4 2 3 decnncl ⊢ 12 ∈ ℕ
5 1 4 ndxid ⊢ dist = Slot dist ⁡ ndx