Metamath Proof Explorer


Theorem dvfcn

Description: The derivative is a function. (Contributed by Mario Carneiro, 9-Feb-2015)

Ref Expression
Assertion dvfcn ⊢ F ℂ ′ : dom ⁡ F ℂ ′ ⟶ ℂ

Proof

Step Hyp Ref Expression
1 cnelprrecn ⊢ ℂ ∈ ℝ ℂ
2 dvfg ⊢ ℂ ∈ ℝ ℂ → F ℂ ′ : dom ⁡ F ℂ ′ ⟶ ℂ
3 1 2 ax-mp ⊢ F ℂ ′ : dom ⁡ F ℂ ′ ⟶ ℂ