Metamath Proof Explorer


Theorem e01an

Description: Conjunction form of e01 . (Contributed by Alan Sare, 11-Jun-2011) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Hypotheses e01an.1 ⊢ φ
e01an.2 ⊢ ψ → χ
e01an.3 ⊢ φ ∧ χ → θ
Assertion e01an ⊢ ψ → θ

Proof

Step Hyp Ref Expression
1 e01an.1 ⊢ φ
2 e01an.2 ⊢ ψ → χ
3 e01an.3 ⊢ φ ∧ χ → θ
4 3 ex ⊢ φ → χ → θ
5 1 2 4 e01 ⊢ ψ → θ