Metamath Proof Explorer


Theorem elabd

Description: Explicit demonstration the class { x | ps } is not empty by the example A . (Contributed by RP, 12-Aug-2020) (Revised by AV, 23-Mar-2024)

Ref Expression
Hypotheses elabd.1 ⊢ φ → A ∈ V
elabd.2 ⊢ φ → χ
elabd.3 ⊢ x = A → ψ ↔ χ
Assertion elabd ⊢ φ → A ∈ x | ψ

Proof

Step Hyp Ref Expression
1 elabd.1 ⊢ φ → A ∈ V
2 elabd.2 ⊢ φ → χ
3 elabd.3 ⊢ x = A → ψ ↔ χ
4 3 elabg ⊢ A ∈ V → A ∈ x | ψ ↔ χ
5 1 4 syl ⊢ φ → A ∈ x | ψ ↔ χ
6 2 5 mpbird ⊢ φ → A ∈ x | ψ