Metamath Proof Explorer


Theorem elpsseu

Description: A class has a unique element just in case it has a unique proper subset. (Contributed by Adrian Ducourtial, 26-Oct-2026)

Ref Expression
Assertion elpsseu ⊢ ∃! x x ∈ A ↔ ∃! y y ⊂ A

Proof

Step Hyp Ref Expression
1 elpssex ⊢ ∃ x x ∈ A ↔ ∃ y y ⊂ A
2 elpssmo ⊢ ∃* x x ∈ A ↔ ∃* y y ⊂ A
3 1 2 anbi12i ⊢ ∃ x x ∈ A ∧ ∃* x x ∈ A ↔ ∃ y y ⊂ A ∧ ∃* y y ⊂ A
4 df-eu ⊢ ∃! x x ∈ A ↔ ∃ x x ∈ A ∧ ∃* x x ∈ A
5 df-eu ⊢ ∃! y y ⊂ A ↔ ∃ y y ⊂ A ∧ ∃* y y ⊂ A
6 3 4 5 3bitr4i ⊢ ∃! x x ∈ A ↔ ∃! y y ⊂ A