Metamath Proof Explorer


Theorem elqsi

Description: Membership in a quotient set. (Contributed by NM, 23-Jul-1995)

Ref Expression
Assertion elqsi ⊢ B ∈ A / R → ∃ x ∈ A B = x R

Proof

Step Hyp Ref Expression
1 elqsg ⊢ B ∈ A / R → B ∈ A / R ↔ ∃ x ∈ A B = x R
2 1 ibi ⊢ B ∈ A / R → ∃ x ∈ A B = x R