Metamath Proof Explorer


Theorem elqsg

Description: Closed form of elqs . (Contributed by Rodolfo Medina, 12-Oct-2010)

Ref Expression
Assertion elqsg ⊢ B ∈ V → B ∈ A / R ↔ ∃ x ∈ A B = x R

Proof

Step Hyp Ref Expression
1 eqeq1 ⊢ y = B → y = x R ↔ B = x R
2 1 rexbidv ⊢ y = B → ∃ x ∈ A y = x R ↔ ∃ x ∈ A B = x R
3 df-qs ⊢ A / R = y | ∃ x ∈ A y = x R
4 2 3 elab2g ⊢ B ∈ V → B ∈ A / R ↔ ∃ x ∈ A B = x R