Metamath Proof Explorer
Description: Membership in a class abstraction, using implicit substitution.
(Contributed by NM, 13-Sep-1995)
|
|
Ref |
Expression |
|
Hypotheses |
elab2g.1 |
|
|
|
elab2g.2 |
|
|
Assertion |
elab2g |
|
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
elab2g.1 |
|
2 |
|
elab2g.2 |
|
3 |
2
|
eleq2i |
|
4 |
1
|
elabg |
|
5 |
3 4
|
syl5bb |
|