Metamath Proof Explorer


Theorem eleq2i

Description: Inference from equality to equivalence of membership. (Contributed by NM, 26-May-1993)

Ref Expression
Hypothesis eleq1i.1 A=B
Assertion eleq2i CACB

Proof

Step Hyp Ref Expression
1 eleq1i.1 A=B
2 eleq2 A=BCACB
3 1 2 ax-mp CACB