Metamath Proof Explorer


Theorem equs4v

Description: Version of equs4 with a disjoint variable condition, which requires fewer axioms. (Contributed by NM, 10-May-1993) (Revised by BJ, 31-May-2019)

Ref Expression
Assertion equs4v x x = y φ x x = y φ

Proof

Step Hyp Ref Expression
1 ax6ev x x = y
2 exintr x x = y φ x x = y x x = y φ
3 1 2 mpi x x = y φ x x = y φ