Metamath Proof Explorer


Theorem equs4v

Description: Version of equs4 with a disjoint variable condition, which requires fewer axioms. (Contributed by NM, 10-May-1993) (Revised by BJ, 31-May-2019)

Ref Expression
Assertion equs4v ⊢ ∀ x x = y → φ → ∃ x x = y ∧ φ

Proof

Step Hyp Ref Expression
1 ax6ev ⊢ ∃ x x = y
2 exintr ⊢ ∀ x x = y → φ → ∃ x x = y → ∃ x x = y ∧ φ
3 1 2 mpi ⊢ ∀ x x = y → φ → ∃ x x = y ∧ φ