Metamath Proof Explorer


Theorem evpmval

Description: Value of the set of even permutations, the alternating group. (Contributed by Thierry Arnoux, 1-Nov-2023)

Ref Expression
Hypothesis evpmval.1 ⊢ A = pmEven ⁡ D
Assertion evpmval ⊢ D ∈ V → A = pmSgn ⁡ D -1 1

Proof

Step Hyp Ref Expression
1 evpmval.1 ⊢ A = pmEven ⁡ D
2 elex ⊢ D ∈ V → D ∈ V
3 fveq2 ⊢ d = D → pmSgn ⁡ d = pmSgn ⁡ D
4 3 cnveqd ⊢ d = D → pmSgn ⁡ d -1 = pmSgn ⁡ D -1
5 4 imaeq1d ⊢ d = D → pmSgn ⁡ d -1 1 = pmSgn ⁡ D -1 1
6 df-evpm ⊢ pmEven = d ∈ V ⟼ pmSgn ⁡ d -1 1
7 fvex ⊢ pmSgn ⁡ D ∈ V
8 7 cnvex ⊢ pmSgn ⁡ D -1 ∈ V
9 8 imaex ⊢ pmSgn ⁡ D -1 1 ∈ V
10 5 6 9 fvmpt ⊢ D ∈ V → pmEven ⁡ D = pmSgn ⁡ D -1 1
11 2 10 syl ⊢ D ∈ V → pmEven ⁡ D = pmSgn ⁡ D -1 1
12 1 11 eqtrid ⊢ D ∈ V → A = pmSgn ⁡ D -1 1