Metamath Proof Explorer


Theorem flidm

Description: The floor function is idempotent. (Contributed by NM, 17-Aug-2008)

Ref Expression
Assertion flidm ⊢ A ∈ ℝ → A = A

Proof

Step Hyp Ref Expression
1 flcl ⊢ A ∈ ℝ → A ∈ ℤ
2 flid ⊢ A ∈ ℤ → A = A
3 1 2 syl ⊢ A ∈ ℝ → A = A