Metamath Proof Explorer


Theorem fneq2

Description: Equality theorem for function predicate with domain. (Contributed by NM, 1-Aug-1994)

Ref Expression
Assertion fneq2 A=BFFnAFFnB

Proof

Step Hyp Ref Expression
1 eqeq2 A=BdomF=AdomF=B
2 1 anbi2d A=BFunFdomF=AFunFdomF=B
3 df-fn FFnAFunFdomF=A
4 df-fn FFnBFunFdomF=B
5 2 3 4 3bitr4g A=BFFnAFFnB