Metamath Proof Explorer


Theorem fnfund

Description: A function with domain is a function, deduction form. (Contributed by Jonathan Ben-Naim, 3-Jun-2011)

Ref Expression
Hypothesis fnfund.1 φFFnA
Assertion fnfund φFunF

Proof

Step Hyp Ref Expression
1 fnfund.1 φFFnA
2 fnfun FFnAFunF
3 1 2 syl φFunF