Theorem fnfund

Description: A function with domain is a function, deduction form. (Contributed by Jonathan Ben-Naim, 3-Jun-2011)

	Ref	Expression
Hypothesis	fnfund.1	$$⊢\phi \to FFnA$$
Assertion	fnfund	$$⊢\phi \to \mathrm{Fun}F$$

Proof

Step	Hyp	Ref	Expression
1		fnfund.1	$$⊢\phi \to FFnA$$
2		fnfun	$$⊢FFnA\to \mathrm{Fun}F$$
3	1 2	syl	$$⊢\phi \to \mathrm{Fun}F$$