Metamath Proof Explorer


Theorem frege55lem1c

Description: Necessary deduction regarding substitution of value in equality. (Contributed by RP, 24-Dec-2019)

Ref Expression
Assertion frege55lem1c φ [˙A / x]˙ x = B φ A = B

Proof

Step Hyp Ref Expression
1 df-sbc [˙A / x]˙ x = B A x | x = B
2 eqeq1 x = A x = B A = B
3 2 elabg A x | x = B A x | x = B A = B
4 3 ibi A x | x = B A = B
5 1 4 sylbi [˙A / x]˙ x = B A = B
6 5 imim2i φ [˙A / x]˙ x = B φ A = B