Metamath Proof Explorer


Theorem hlcomd

Description: The half-line relation is symmetric. Theorem 6.6 of Schwabhauser p. 44. (Contributed by Thierry Arnoux, 21-Feb-2020)

Ref Expression
Hypotheses ishlg.p ⊢ P = Base G
ishlg.i ⊢ I = Itv ⁡ G
ishlg.k ⊢ K = hl 𝒢 ⁡ G
ishlg.a ⊢ φ → A ∈ P
ishlg.b ⊢ φ → B ∈ P
ishlg.c ⊢ φ → C ∈ P
ishlg.g ⊢ φ → G ∈ V
hlcomd.1 ⊢ φ → A K ⁡ C B
Assertion hlcomd ⊢ φ → B K ⁡ C A

Proof

Step Hyp Ref Expression
1 ishlg.p ⊢ P = Base G
2 ishlg.i ⊢ I = Itv ⁡ G
3 ishlg.k ⊢ K = hl 𝒢 ⁡ G
4 ishlg.a ⊢ φ → A ∈ P
5 ishlg.b ⊢ φ → B ∈ P
6 ishlg.c ⊢ φ → C ∈ P
7 ishlg.g ⊢ φ → G ∈ V
8 hlcomd.1 ⊢ φ → A K ⁡ C B
9 1 2 3 4 5 6 7 hlcomb ⊢ φ → A K ⁡ C B ↔ B K ⁡ C A
10 8 9 mpbid ⊢ φ → B K ⁡ C A