Metamath Proof Explorer


Theorem hvsubval

Description: Value of vector subtraction. (Contributed by NM, 5-Sep-1999) (Revised by Mario Carneiro, 23-Dec-2013) (New usage is discouraged.)

Ref Expression
Assertion hvsubval ⊢ A ∈ ℋ ∧ B ∈ ℋ → A - ℎ B = A + ℎ -1 ⋅ ℎ B

Proof

Step Hyp Ref Expression
1 oveq1 ⊢ x = A → x + ℎ -1 ⋅ ℎ y = A + ℎ -1 ⋅ ℎ y
2 oveq2 ⊢ y = B → -1 ⋅ ℎ y = -1 ⋅ ℎ B
3 2 oveq2d ⊢ y = B → A + ℎ -1 ⋅ ℎ y = A + ℎ -1 ⋅ ℎ B
4 df-hvsub ⊢ - ℎ = x ∈ ℋ , y ∈ ℋ ⟼ x + ℎ -1 ⋅ ℎ y
5 ovex ⊢ A + ℎ -1 ⋅ ℎ B ∈ V
6 1 3 4 5 ovmpo ⊢ A ∈ ℋ ∧ B ∈ ℋ → A - ℎ B = A + ℎ -1 ⋅ ℎ B