Metamath Proof Explorer


Theorem hvsubval

Description: Value of vector subtraction. (Contributed by NM, 5-Sep-1999) (Revised by Mario Carneiro, 23-Dec-2013) (New usage is discouraged.)

Ref Expression
Assertion hvsubval ( ( 𝐴 ∈ ℋ ∧ 𝐵 ∈ ℋ ) → ( 𝐴 −ℎ 𝐵 ) = ( 𝐴 +ℎ ( - 1 ·ℎ 𝐵 ) ) )

Proof

Step Hyp Ref Expression
1 oveq1 ⊢ ( 𝑥 = 𝐴 → ( 𝑥 +ℎ ( - 1 ·ℎ 𝑦 ) ) = ( 𝐴 +ℎ ( - 1 ·ℎ 𝑦 ) ) )
2 oveq2 ⊢ ( 𝑦 = 𝐵 → ( - 1 ·ℎ 𝑦 ) = ( - 1 ·ℎ 𝐵 ) )
3 2 oveq2d ⊢ ( 𝑦 = 𝐵 → ( 𝐴 +ℎ ( - 1 ·ℎ 𝑦 ) ) = ( 𝐴 +ℎ ( - 1 ·ℎ 𝐵 ) ) )
4 df-hvsub ⊢ −ℎ = ( 𝑥 ∈ ℋ , 𝑦 ∈ ℋ ↦ ( 𝑥 +ℎ ( - 1 ·ℎ 𝑦 ) ) )
5 ovex ⊢ ( 𝐴 +ℎ ( - 1 ·ℎ 𝐵 ) ) ∈ V
6 1 3 4 5 ovmpo ⊢ ( ( 𝐴 ∈ ℋ ∧ 𝐵 ∈ ℋ ) → ( 𝐴 −ℎ 𝐵 ) = ( 𝐴 +ℎ ( - 1 ·ℎ 𝐵 ) ) )