Metamath Proof Explorer


Theorem ifcl

Description: Membership (closure) of a conditional operator. (Contributed by NM, 4-Apr-2005)

Ref Expression
Assertion ifcl ⊢ A ∈ C ∧ B ∈ C → if φ A B ∈ C

Proof

Step Hyp Ref Expression
1 eleq1 ⊢ A = if φ A B → A ∈ C ↔ if φ A B ∈ C
2 eleq1 ⊢ B = if φ A B → B ∈ C ↔ if φ A B ∈ C
3 1 2 ifboth ⊢ A ∈ C ∧ B ∈ C → if φ A B ∈ C