Metamath Proof Explorer


Theorem eleq1

Description: Equality implies equivalence of membership. (Contributed by NM, 26-May-1993) (Proof shortened by Wolf Lammen, 20-Nov-2019)

Ref Expression
Assertion eleq1 A=BACBC

Proof

Step Hyp Ref Expression
1 id A=BA=B
2 1 eleq1d A=BACBC