Metamath Proof Explorer


Theorem iineq2dv

Description: Equality deduction for indexed intersection. (Contributed by NM, 3-Aug-2004)

Ref Expression
Hypothesis iuneq2dv.1 φ x A B = C
Assertion iineq2dv φ x A B = x A C

Proof

Step Hyp Ref Expression
1 iuneq2dv.1 φ x A B = C
2 nfv x φ
3 2 1 iineq2d φ x A B = x A C