Metamath Proof Explorer


Theorem iineq2d

Description: Equality deduction for indexed intersection. (Contributed by NM, 7-Dec-2011)

Ref Expression
Hypotheses iineq2d.1 x φ
iineq2d.2 φ x A B = C
Assertion iineq2d φ x A B = x A C

Proof

Step Hyp Ref Expression
1 iineq2d.1 x φ
2 iineq2d.2 φ x A B = C
3 1 2 ralrimia φ x A B = C
4 iineq2 x A B = C x A B = x A C
5 3 4 syl φ x A B = x A C