Metamath Proof Explorer


Theorem iineq2d

Description: Equality deduction for indexed intersection. (Contributed by NM, 7-Dec-2011)

Ref Expression
Hypotheses iineq2d.1 𝑥 𝜑
iineq2d.2 ( ( 𝜑𝑥𝐴 ) → 𝐵 = 𝐶 )
Assertion iineq2d ( 𝜑 𝑥𝐴 𝐵 = 𝑥𝐴 𝐶 )

Proof

Step Hyp Ref Expression
1 iineq2d.1 𝑥 𝜑
2 iineq2d.2 ( ( 𝜑𝑥𝐴 ) → 𝐵 = 𝐶 )
3 1 2 ralrimia ( 𝜑 → ∀ 𝑥𝐴 𝐵 = 𝐶 )
4 iineq2 ( ∀ 𝑥𝐴 𝐵 = 𝐶 𝑥𝐴 𝐵 = 𝑥𝐴 𝐶 )
5 3 4 syl ( 𝜑 𝑥𝐴 𝐵 = 𝑥𝐴 𝐶 )