Metamath Proof Explorer


Theorem imdivd

Description: Imaginary part of a division. Related to remul2 . (Contributed by Mario Carneiro, 29-May-2016)

Ref Expression
Hypotheses crred.1 ⊢ φ → A ∈ ℝ
remul2d.2 ⊢ φ → B ∈ ℂ
redivd.2 ⊢ φ → A ≠ 0
Assertion imdivd ⊢ φ → ℑ ⁡ B A = ℑ ⁡ B A

Proof

Step Hyp Ref Expression
1 crred.1 ⊢ φ → A ∈ ℝ
2 remul2d.2 ⊢ φ → B ∈ ℂ
3 redivd.2 ⊢ φ → A ≠ 0
4 imdiv ⊢ B ∈ ℂ ∧ A ∈ ℝ ∧ A ≠ 0 → ℑ ⁡ B A = ℑ ⁡ B A
5 2 1 3 4 syl3anc ⊢ φ → ℑ ⁡ B A = ℑ ⁡ B A