Metamath Proof Explorer


Theorem incom

Description: Commutative law for intersection of classes. Exercise 7 of TakeutiZaring p. 17. (Contributed by NM, 21-Jun-1993) (Proof shortened by SN, 12-Dec-2023)

Ref Expression
Assertion incom A B = B A

Proof

Step Hyp Ref Expression
1 rabswap x A | x B = x B | x A
2 dfin5 A B = x A | x B
3 dfin5 B A = x B | x A
4 1 2 3 3eqtr4i A B = B A