Metamath Proof Explorer


Theorem inindi

Description: Intersection distributes over itself. (Contributed by NM, 6-May-1994)

Ref Expression
Assertion inindi ⊢ A ∩ B ∩ C = A ∩ B ∩ A ∩ C

Proof

Step Hyp Ref Expression
1 inidm ⊢ A ∩ A = A
2 1 ineq1i ⊢ A ∩ A ∩ B ∩ C = A ∩ B ∩ C
3 in4 ⊢ A ∩ A ∩ B ∩ C = A ∩ B ∩ A ∩ C
4 2 3 eqtr3i ⊢ A ∩ B ∩ C = A ∩ B ∩ A ∩ C