Metamath Proof Explorer


Theorem inteqd

Description: Equality deduction for class intersection. (Contributed by NM, 2-Sep-2003)

Ref Expression
Hypothesis inteqd.1 ⊢ φ → A = B
Assertion inteqd ⊢ φ → ⋂ A = ⋂ B

Proof

Step Hyp Ref Expression
1 inteqd.1 ⊢ φ → A = B
2 inteq ⊢ A = B → ⋂ A = ⋂ B
3 1 2 syl ⊢ φ → ⋂ A = ⋂ B