Metamath Proof Explorer


Theorem iotasbc5

Description: Theorem *14.205 in WhiteheadRussell p. 190. (Contributed by Andrew Salmon, 11-Jul-2011)

Ref Expression
Assertion iotasbc5 ⊢ ∃! x φ → [˙ ι x | φ / y]˙ ψ ↔ ∃ y y = ι x | φ ∧ ψ

Proof

Step Hyp Ref Expression
1 sbc5 ⊢ [˙ ι x | φ / y]˙ ψ ↔ ∃ y y = ι x | φ ∧ ψ
2 1 a1i ⊢ ∃! x φ → [˙ ι x | φ / y]˙ ψ ↔ ∃ y y = ι x | φ ∧ ψ