Metamath Proof Explorer


Theorem issubgoilem

Description: Lemma for hhssabloilem . (Contributed by Paul Chapman, 25-Feb-2008) (New usage is discouraged.)

Ref Expression
Hypothesis issubgoilem.1 ⊢ x ∈ Y ∧ y ∈ Y → x H y = x G y
Assertion issubgoilem ⊢ A ∈ Y ∧ B ∈ Y → A H B = A G B

Proof

Step Hyp Ref Expression
1 issubgoilem.1 ⊢ x ∈ Y ∧ y ∈ Y → x H y = x G y
2 oveq1 ⊢ x = A → x H y = A H y
3 oveq1 ⊢ x = A → x G y = A G y
4 2 3 eqeq12d ⊢ x = A → x H y = x G y ↔ A H y = A G y
5 oveq2 ⊢ y = B → A H y = A H B
6 oveq2 ⊢ y = B → A G y = A G B
7 5 6 eqeq12d ⊢ y = B → A H y = A G y ↔ A H B = A G B
8 4 7 1 vtocl2ga ⊢ A ∈ Y ∧ B ∈ Y → A H B = A G B