Metamath Proof Explorer


Theorem lnoppinn0

Description: The segment between two points X and Y on opposite sides of a line D intersects D . (Contributed by Thierry Arnoux, 23-Aug-2026)

Ref Expression
Hypotheses lnoppinn0.p P = Base G
lnoppinn0.i I = Itv G
lnoppinn0.l L = Line 𝒢 G
lnoppinn0.o O = a b | a P D b P D t D t a I b
lnoppinn0.g φ G V
lnoppinn0.d φ D ran L
lnoppinn0.x φ X P
lnoppinn0.y φ Y P
lnoppinn0.1 φ X O Y
Assertion lnoppinn0 φ D X I Y

Proof

Step Hyp Ref Expression
1 lnoppinn0.p P = Base G
2 lnoppinn0.i I = Itv G
3 lnoppinn0.l L = Line 𝒢 G
4 lnoppinn0.o O = a b | a P D b P D t D t a I b
5 lnoppinn0.g φ G V
6 lnoppinn0.d φ D ran L
7 lnoppinn0.x φ X P
8 lnoppinn0.y φ Y P
9 lnoppinn0.1 φ X O Y
10 simplr φ t D t X I Y t D
11 simpr φ t D t X I Y t X I Y
12 10 11 elind φ t D t X I Y t D X I Y
13 12 ne0d φ t D t X I Y D X I Y
14 eqid dist G = dist G
15 1 14 2 4 7 8 islnopp φ X O Y ¬ X D ¬ Y D t D t X I Y
16 9 15 mpbid φ ¬ X D ¬ Y D t D t X I Y
17 16 simprd φ t D t X I Y
18 13 17 r19.29a φ D X I Y