Metamath Proof Explorer


Theorem lsw0g

Description: The last symbol of an empty word does not exist. (Contributed by Alexander van der Vekens, 11-Nov-2018)

Ref Expression
Assertion lsw0g lastS =

Proof

Step Hyp Ref Expression
1 wrd0 Word V
2 hash0 = 0
3 lsw0 Word V = 0 lastS =
4 1 2 3 mp2an lastS =