Metamath Proof Explorer


Theorem matvsca

Description: The matrix ring has the same scalar multiplication as its underlying linear structure. (Contributed by Stefan O'Rear, 4-Sep-2015)

Ref Expression
Hypotheses matbas.a A = N Mat R
matbas.g G = R freeLMod N × N
Assertion matvsca N Fin R V G = A

Proof

Step Hyp Ref Expression
1 matbas.a A = N Mat R
2 matbas.g G = R freeLMod N × N
3 eqid R maMul N N N = R maMul N N N
4 1 2 3 matval N Fin R V A = G sSet ndx R maMul N N N
5 4 fveq2d N Fin R V A = G sSet ndx R maMul N N N
6 vscaid 𝑠 = Slot ndx
7 vscandx ndx = 6
8 3re 3
9 3lt6 3 < 6
10 8 9 gtneii 6 3
11 mulrndx ndx = 3
12 10 11 neeqtrri 6 ndx
13 7 12 eqnetri ndx ndx
14 6 13 setsnid G = G sSet ndx R maMul N N N
15 5 14 syl6reqr N Fin R V G = A