Metamath Proof Explorer

Theorem mdandyvrx11

Description: Given the exclusivities set in the hypotheses, there exist a proof where ch, th, ta, et exclude ze, si accordingly. (Contributed by Jarvin Udandy, 7-Sep-2016)

		Ref	Expression
	Hypotheses	mdandyvrx11.1	$⊢ (φ ⊻ ζ)$
		mdandyvrx11.2	$⊢ (ψ ⊻ σ)$
		mdandyvrx11.3	$⊢ χ \leftrightarrow ψ$
		mdandyvrx11.4	$⊢ θ \leftrightarrow ψ$
		mdandyvrx11.5	$⊢ τ \leftrightarrow φ$
		mdandyvrx11.6	$⊢ η \leftrightarrow ψ$
	Assertion	mdandyvrx11	$⊢ ((((χ ⊻ σ) \land (θ ⊻ σ)) \land (τ ⊻ ζ)) \land (η ⊻ σ))$

Proof

Step	Hyp	Ref	Expression
1		mdandyvrx11.1	$⊢ (φ ⊻ ζ)$
2		mdandyvrx11.2	$⊢ (ψ ⊻ σ)$
3		mdandyvrx11.3	$⊢ χ \leftrightarrow ψ$
4		mdandyvrx11.4	$⊢ θ \leftrightarrow ψ$
5		mdandyvrx11.5	$⊢ τ \leftrightarrow φ$
6		mdandyvrx11.6	$⊢ η \leftrightarrow ψ$
7	2 1 3 4 5 6	mdandyvrx4	$⊢ ((((χ ⊻ σ) \land (θ ⊻ σ)) \land (τ ⊻ ζ)) \land (η ⊻ σ))$