Metamath Proof Explorer


Theorem merlem5

Description: Step 11 of Meredith's proof of Lukasiewicz axioms from his sole axiom. (Contributed by NM, 14-Dec-2002) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion merlem5 ⊢ φ → ψ → ¬ ¬ φ → ψ

Proof

Step Hyp Ref Expression
1 meredith ⊢ ψ → ψ → ¬ ψ → ¬ ψ → ψ → ψ → ψ → ψ → ψ → ψ
2 meredith ⊢ ψ → ψ → ¬ ψ → ¬ ¬ ¬ φ → ψ → φ → φ → ψ → ¬ ¬ φ → ψ
3 merlem1 ⊢ φ → ψ → ¬ ¬ φ → ψ → ¬ ψ → ψ → ¬ ψ → ¬ ψ → ψ → ψ → ψ → ψ → ψ → ψ → ¬ φ → ¬ ψ → ψ → ¬ ψ → ¬ ψ → ψ → ψ → ψ → ψ → ψ → ψ
4 merlem4 ⊢ φ → ψ → ¬ ¬ φ → ψ → ¬ ψ → ψ → ¬ ψ → ¬ ψ → ψ → ψ → ψ → ψ → ψ → ψ → ¬ φ → ¬ ψ → ψ → ¬ ψ → ¬ ψ → ψ → ψ → ψ → ψ → ψ → ψ → φ → ψ → ¬ ¬ φ → ψ → ¬ ψ → ψ → ¬ ψ → ¬ ψ → ψ → ψ → ψ → ψ → ψ → ψ → ¬ φ → ¬ ψ → ψ → ¬ ψ → ¬ ψ → ψ → ψ → ψ → ψ → ψ → ψ → φ → ψ → ψ → ¬ ψ → ¬ ¬ ¬ φ → ψ → φ
5 3 4 ax-mp ⊢ φ → ψ → ¬ ¬ φ → ψ → ¬ ψ → ψ → ¬ ψ → ¬ ψ → ψ → ψ → ψ → ψ → ψ → ψ → ¬ φ → ¬ ψ → ψ → ¬ ψ → ¬ ψ → ψ → ψ → ψ → ψ → ψ → ψ → φ → ψ → ψ → ¬ ψ → ¬ ¬ ¬ φ → ψ → φ
6 meredith ⊢ φ → ψ → ¬ ¬ φ → ψ → ¬ ψ → ψ → ¬ ψ → ¬ ψ → ψ → ψ → ψ → ψ → ψ → ψ → ¬ φ → ¬ ψ → ψ → ¬ ψ → ¬ ψ → ψ → ψ → ψ → ψ → ψ → ψ → φ → ψ → ψ → ¬ ψ → ¬ ¬ ¬ φ → ψ → φ → ψ → ψ → ¬ ψ → ¬ ¬ ¬ φ → ψ → φ → φ → ψ → ¬ ¬ φ → ψ → ψ → ψ → ¬ ψ → ¬ ψ → ψ → ψ → ψ → ψ → ψ → ψ → φ → ψ → ¬ ¬ φ → ψ
7 5 6 ax-mp ⊢ ψ → ψ → ¬ ψ → ¬ ¬ ¬ φ → ψ → φ → φ → ψ → ¬ ¬ φ → ψ → ψ → ψ → ¬ ψ → ¬ ψ → ψ → ψ → ψ → ψ → ψ → ψ → φ → ψ → ¬ ¬ φ → ψ
8 2 7 ax-mp ⊢ ψ → ψ → ¬ ψ → ¬ ψ → ψ → ψ → ψ → ψ → ψ → ψ → φ → ψ → ¬ ¬ φ → ψ
9 1 8 ax-mp ⊢ φ → ψ → ¬ ¬ φ → ψ