Metamath Proof Explorer


Theorem mpjaod

Description: Eliminate a disjunction in a deduction. (Contributed by Mario Carneiro, 29-May-2016)

Ref Expression
Hypotheses jaod.1 φψχ
jaod.2 φθχ
jaod.3 φψθ
Assertion mpjaod φχ

Proof

Step Hyp Ref Expression
1 jaod.1 φψχ
2 jaod.2 φθχ
3 jaod.3 φψθ
4 1 2 jaod φψθχ
5 3 4 mpd φχ