Metamath Proof Explorer


Theorem mulscan1d

Description: Cancellation of surreal multiplication when the left term is nonzero. (Contributed by Scott Fenton, 10-Mar-2025)

Ref Expression
Hypotheses mulscan2d.1 ⊢ φ → A ∈ No
mulscan2d.2 ⊢ φ → B ∈ No
mulscan2d.3 ⊢ φ → C ∈ No
mulscan2d.4 ⊢ φ → C ≠ 0 s
Assertion mulscan1d ⊢ φ → C ⋅ s A = C ⋅ s B ↔ A = B

Proof

Step Hyp Ref Expression
1 mulscan2d.1 ⊢ φ → A ∈ No
2 mulscan2d.2 ⊢ φ → B ∈ No
3 mulscan2d.3 ⊢ φ → C ∈ No
4 mulscan2d.4 ⊢ φ → C ≠ 0 s
5 1 3 mulscomd ⊢ φ → A ⋅ s C = C ⋅ s A
6 2 3 mulscomd ⊢ φ → B ⋅ s C = C ⋅ s B
7 5 6 eqeq12d ⊢ φ → A ⋅ s C = B ⋅ s C ↔ C ⋅ s A = C ⋅ s B
8 1 2 3 4 mulscan2d ⊢ φ → A ⋅ s C = B ⋅ s C ↔ A = B
9 7 8 bitr3d ⊢ φ → C ⋅ s A = C ⋅ s B ↔ A = B